Question

please answer the second question ASAP! ​

Answer 1

Angle M = angle N = 90°.....tangent theorem

OR = hypotenuse =10cm

Radius = OM =ON

= 5cm

$= \frac{1}{2} \times 10$

By converse of 30 60 90 theorem,

If a side is half of hypotenuse, then the angles opposite to that side is 30°

Therefore Angle MRO = 30°

Triangle MRO = Triangle NRO..... Hypotenuse side test.

Thus, angle MRO. =Angle NRO =30°

ANGLE MRO + ANGLE NRO = ANGLE MRN

ANGLE MRN = 30 + 30 = 60°.

Hope this helps

Please mark my answer as BRAINLIEST

Answer 2

if you consider ang. MRO as x

ang. OMR =90° [since angle made by a tangent to the radius of the circle is 90°]

hence sin(x)=OM/OR

=> 5/10

=>1/2

therefore, x=30°[since, sin30°=1/2]

ang.MRO= 30°