Question

if x=-2 and x=-1/5 are the solutions of equation 5x^2 + kx + p = 0, find the values of k and p ​

Answer 1

Answer:

5(-2)^2+k(-2)+p=0

5×4+(-2k)+p=0

20-2k+p=0

p=-20+2k

again,5(-1/5)^2+k(-2)+p=0

-1/5+(-2k)+p=0

p=1/5+2k

a/q, -20+2k=1/5+2k

4k=101/5

k=404/5