if x =2 and x=3 are roots of 3x^2-2px+2q=0 tgen find p+q
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Given :
• Polynomial = 3x² - 2px + 2q = 0
• Two roots of this polynomial :-
- x = 2
- x = 3
To find :
• Value of p + q
Solution :
→ f(x) = 3x² - 2px + 2q = 0
→ x = 2
→ 3(2)² - 2p(2) + 2q = 0
→ 3(4) - 4p + 2q = 0
→ 12 - 4p + 2q = 0
→ 2q - 4p = - 12 -------(1)
→ f(x) = 3x² - 2px + 2q = 0
→ x = 3
→ 3(3)² - 2p(3) + 2q = 0
→ 3(9) - 6p + 2q = 0
→ 27 - 6p + 2q = 0
→ 2q - 6p = - 27 -------(2)
Solving (1) and (2) :-
2q - 4p = - 12
2q - 6p = - 27
(-)⠀(+)⠀⠀(+)
___________
→ 2p = 15
___________
→ 2p = 15
→ p = 15/2
→ p = 7.5
Substituting the value of x in equation (1) :-
→ 2q - 4p = - 12
→ 2q - 4(7.5) = - 12
→ 2q - 30 = - 12
→ 2q = 18
→ q = 18/2
→ q = 8
Therefore, the value of p = 7.5 and q = 8
→ p + q
→ 7.5 + 8
→ 15.5
Therefore, the value of p + q = 15.5
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