If x=2 and x= 3 are roots of equation 3x square -2ax -2b = 0
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Basic point: If a,b are the roots of an eqn, then (x-a)(x-b)=0 be that quadratic equation.
If x = 2/3, x = -3 are roots, then the eqn will be
(x-2/3)(x-(-3))=0
⇒ (x-2/3)(x+3) = 0
⇒ x²-(2/3)x+3x-2 = 0
⇒ 3x²-2x+9x-6=0
⇒ 3x²+7x-6=0 is the required eqn.
Compare the eqn with ax²+7x+b=0
Therefore, a=3, b= -6
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