If x=2 and x=3 are roots of the equation 3x2 - 2Kx+ 2m =0,find the value of K and m.
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Sum of roots = -( coeff.of x)/coeff.of x^2
2+3 = -(-2k)/3
5 = 2k/3
2k = 15
k = 15/2
Product of roots = constant term/ coeff.of x^2
2×3 = 2m/3
6 = 2m/3
m = 6 × 3/2 = 9
2+3 = -(-2k)/3
5 = 2k/3
2k = 15
k = 15/2
Product of roots = constant term/ coeff.of x^2
2×3 = 2m/3
6 = 2m/3
m = 6 × 3/2 = 9
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