If x=-2, and y =-6 is the solution of equation 3 ax+2ay=6 then find the value of b from 2(a-1)+2(3b-4)=4
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Substituting x = 2 and y = 6 in eqn,we get
3 * a * 2 + 2 * b * 6 = 6
6a + 12b = 6
ie a + 2b = 1
so, a = 1 - 2b
Substituting a = 1 - 2b in second equation,we get
2(1 - 2b - 1) + 2(3b - 4) = 4
-4b + 6b - 8 = 4
2b = 12
b = 6
3 * a * 2 + 2 * b * 6 = 6
6a + 12b = 6
ie a + 2b = 1
so, a = 1 - 2b
Substituting a = 1 - 2b in second equation,we get
2(1 - 2b - 1) + 2(3b - 4) = 4
-4b + 6b - 8 = 4
2b = 12
b = 6
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