Math, asked by alfredshaju7, 4 months ago

if x-2 is a factor of p(X)=3ax^ 3-2x^2+x-7 then find the value of a

Answers

Answered by yigi35
0

Answer:

p(x)=3ax cube-2x square+x-7

x - 2 = 0    \\ x = 2 \\

hence x=2

so, p(2)=3a(2) cube-2(2) square+(2)-7=0

=48a-8+2-7=0

=-8+2-7=-48a

=-13=-48a

therefore, a=-48/-13

the minuses will canel

a=48/13

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