Question

if x-2 is a factor of the polynomial 4x²+ax-20 then a is equal to​

Answer 1

Answer:

a =2

Step-by-step explanation:

$let \: p(x) = 4x {}^{2} + ax - 20$

Since x -2 is a factor of p(x)

p(2) = 0

$= > 4 \times 2 {}^{2} + a \times 2 - 20 = 0$

=> 16 + 2a -20= 0

=> 2a -4 = 0

=> 2a = 4

=> a = 4/2

so, a = 2

Answer 2

SOLUTION

GIVEN

x - 2 is a factor of the polynomial 4x² + ax - 20

TO DETERMINE

The value of a

EVALUATION

Here the given polynomial is

4x² + ax - 20

Now it is given that x - 2 is a factor of the polynomial 4x² + ax - 20

Thus we get

$\displaystyle \sf{ 4 \times {(2)}^{2} + (a \times 2) - 20 = 0 }$

$\displaystyle \sf{ \implies 16 +2a - 20 = 0 }$

$\displaystyle \sf{ \implies 2a - 4 = 0 }$

$\displaystyle \sf{ \implies 2a = 4 }$

$\displaystyle \sf{ \implies a = 2 }$

FINAL ANSWER

Hence the required value of a = 2

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