if x+2 is a factor of( x+1)^5 + (2x+k)^3 find k
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2
if x+2 is a factor of given polynomial.
putting x = -2 will make polynomial zero.
so
(-2+1)^5 + (-4+k)^3 = 0
-1 = -(k-4)^3
(k-4)^3 = 1
k-4 = 1
k = 5
putting x = -2 will make polynomial zero.
so
(-2+1)^5 + (-4+k)^3 = 0
-1 = -(k-4)^3
(k-4)^3 = 1
k-4 = 1
k = 5
ashokjha265:
thanks alot
Answered by
3
p(x) = (x+1)^5 + (2 x +k)^3
given x+2 is factor
so x+2 = 0 & x= -2
p(x= -2) = (-2 + 1)^5 + (2(-2) +k)^3
0 = (-1)^5 + (-4 + k)^3
0 = -1 +(-4 +k)^3
(-4 + k)^3 = 1
(-4 + k) = 1^3
-4 + k = 1
k = 1 + 4
k = 5
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