If (x-2) is a factor of x^3-3x^4-ax^3+3ax^2+2ax-4 find the value of a
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p(x)=x^3-3x^4-ax^3+3ax^2+2ax-4.
p(2)=(2)^3-3(2)^4-a(2)^3+3a(2)^2+2a(2)-4.
0(as x-2 is a factor)=8-48-8a+12a+4a-4.
0=-44+8a.
8a=44.
a=44/8.
a=5.5
Thus,the value of a is 5.5
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