If (x-2) is a factor of (x²- 3ax + 3a - 7). then find the value of a?
Answers
Answered by
4
Answer:
p(x)=x^2-3ax+3a-7
p(2)=(2)^2-3a(2)+3a-7=0
4-6a+3a-7=0
-3a-3=0
-3a=3
a=-1
Answered by
2
Answer:
Step-by-step explanation:
(x-2)=0
x=2
Now putting the value of x in the given equation
(2^2-3×2a+3a-7)=0
4-6a+3a-7=0
-11-3a=0
-(11+3a)=0
11+3a=0
3a=-11
a=-11/3
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