If x+2 is a factor of x2+ax+2band a+b=4 then find the value of a and b are
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x+2is a factor so p(-2)=0
x²+ax+2b=0=
4-2a+2b=0
4-2(a-b)=0
-2(a-b)= -4
a-b=2
a+b=4
4-2= a+b-(a-b)
2=2b
b=1
therefore
a=3
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Answered by
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Answer:
a=3; b=1
Step-by-step explanation:
p(x) = x^2 + ax +2
p(x) = (x + 2)Q(x) + 0
if x = -2
p(-2) = 0
(-2)^2 + (-2)a + 2 = 0
6-2a=0
a = 3
a + b = 4
subsituting the value of a
3 + b = 4
b =1
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