If x+2 is a factor of x2 +ax+8 then a =.....
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Hey Buddy
Here's The Answer
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Let,
p(x) = x² + ax + 8
Given : x + 2 is factor of p(x)
=> x + 2 = 0
=> x = -2
Then by factor theorem p( -2 ) = 0
=> p( x ) = x² + ax + 8
=> p( -2 ) = ( -2 )² - 2a + 8 = 0
=> 4 - 2a + 8 = 0
=> 12 - 2a = 0
=> 2a = 12
=> a = 6 ✓
Hope It Helps.
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