Question

If (x—2) is a factor of x³—6x²+12x—k, then value of K is

Answer 1

Answer:

The value of K is 8

Step-by-step explanation:

(x-2) is a factor of x³-6x²+12x-k

So,x=2

Put x=2 in the x³-6x²+12x-k

So, (2)³- 6(2)²+12(2)-k =0

8-6(4)+24-k=0

8-k=0

K = 8

Answer 2

Answer:

x-2 = 0

x=2

x^3-6x+12x-k =0

2^3 - 6×(2) ^ 2+ 12×2 = k

8-24+24 = k

8= k

value of k = 8