Question

if (x-2) is a factor of x3+ax2+bx+16 and a-b=6 then find the value of a and b

Answer 1

as (x-2) is factor put X=2 is zero of this eq .
2^3+a2^2+2b+16=0
8+4a+2b+16=0
2a+b=-12..........1
a-b=6...........2
adding 1+2
3a=-6
a=-2
put in 2 we get
-b=8
b=-8