Question

If (x-2) is a factor of x³-mx2+10x-20 then find the value of m.

Answer 1

$\textbf{Answer :}$

Let us take,

f (x) = x³ - mx² + 10x - 20

Since (x - 2) is a factor of f (x),

f (2) = 0

or, 2³ - m (2²) + 10 (2) - 20 = 0

or, 8 - m (4) + 20 - 20 = 0

or, 8 - 4m = 0

or, 4m = 8

or, m = 8/4

or, m = 2

Therefore, the required value of m be $\bold{2}$

#$\bold{MarkAsBrainliest}$

Answer 2

Hey there!

According to factor theorem, If ( x - a) is a factor of f(x ) then f(a) = 0 .

In the same way,
Here f(x) = x³-mx²+10x-20

So if (x-2) is a factor of f(x) , f(2) = 0 .

Now,
f ( 2 ) = 0
2³ -m(2²)+10(2)-20 = 0
8 -4m = 0
8 = 4m
m = 2 .

Therefore, The value of m is 2 .