The difference between the length and breadth of a rectangle is 23m. If its perimeter is 206m, then its area is
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Answered by
4
l - b = 23
and
2(l+b) = 206
l+b = 103
from l-b=23 and l+b=103
we get that l = 63 m and b = 40 m
area of rectangle = l*b
= 63*40
= 2520 m^2
and
2(l+b) = 206
l+b = 103
from l-b=23 and l+b=103
we get that l = 63 m and b = 40 m
area of rectangle = l*b
= 63*40
= 2520 m^2
Answered by
0
L-B=23
perimeter=206 (ie =2(l+b))
L+B=103
L-B=23
2L=126
L=63m,B=40m
area LB=2520m2
perimeter=206 (ie =2(l+b))
L+B=103
L-B=23
2L=126
L=63m,B=40m
area LB=2520m2
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