if x=2 is a root of polynomial f(x)=2x^3-3x+7a, find value of a
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Answered by
3
Put x = 2 and equate to zero
2 (8) - 3(2) + 7a = 0
16 - 6 + 7a = 0
7a = -10
a = -10/7
2 (8) - 3(2) + 7a = 0
16 - 6 + 7a = 0
7a = -10
a = -10/7
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Answered by
1
Hey ! ! !
Mate :-
______________________________________________________________________
Solution :-
put the value of x in f ( x )
f ( 2 ) = 2 (2)*3 - 3 (2) + 7a = 0
:- 16 - 6 + 7a = 0
:- 7a = - 10
:- a = -10/7
______________________________________________________________________
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
Mate :-
______________________________________________________________________
Solution :-
put the value of x in f ( x )
f ( 2 ) = 2 (2)*3 - 3 (2) + 7a = 0
:- 16 - 6 + 7a = 0
:- 7a = - 10
:- a = -10/7
______________________________________________________________________
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
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