Question

if x=2 is a solution of the quadratic equations kx^2+2x-3=0 find the value of k

plz plz quickly as possible as ​

Answer 1

kx ^2+2x-3=0 when x=2
k(2)^2+2(2)-3=0
4k+4-3=0
4k+4=3
4k=-1
k= -1/4

Answer 2

HEY BUDDY HERE IS UR ANSWER !!!

Kx^2 + 2x - 3 = 0 ( x = 2 )
K (2)^2 + 2 (2) - 3 = 0
K (4) + 4 - 3 = 0
4K + 1 = 0
4K = - 1
K = - 1 / 4

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