state and prove law of conservation of momentum
Answers
As per the law of conservation of momentum,when no external unbalanced force is acting on the system total momentum of system remain conserved.
During collision ball A exert an action force Fab on wball B as a result of which its Momentum changes from m2u2 toM2V2 if T be the time of Collision, then according to Newton's second law of motion, force Fab is equal to the rate of change of momentum of B,i.e,
Fab=m2(v2-u2)/t. .......(i)
During collision, as per Newton's third law of motion the ball B exerts a reaction force Fab=-Fab on ball A, as a result of which, its momentum changes from m1u1 to m1v1.
As before,we can write,
Fba=-Fab=m1(v1-u1)/t. .....(ii)
On adding (i) and (ii),we get,
0=m2(v2-u2)/t+m1(v1-u1)/t
m2v2+m1v1=m2u2+m1u1
Thus,total momentum of the balls remains conserved during their collision.
ᴀɴsᴡᴇʀ࿐
ᴅᴇғɪɴɪᴛɪᴏɴ:-
ᴍᴏᴍᴇɴᴛᴜᴍ ɪs ᴛʜᴇ ᴛʜᴇ ᴀᴍᴏᴜɴᴛ ᴏғ ᴍᴏᴛɪᴏɴ ᴏғ ᴀ ᴍᴏᴠɪɴɢ ʙᴏᴅʏ, ᴍᴇᴀsᴜʀᴇᴅ ᴀs ᴀ ᴘʀᴏᴅᴜᴄᴛ ᴏғ ɪᴛs ᴍᴀss ᴀɴᴅ ᴠᴇʟᴏᴄɪᴛʏ.
=>ᴍᴏᴍᴇɴᴛᴜᴍ= ᴍᴀss × ᴠᴇʟᴏᴄɪᴛʏ
ᴅɪᴍᴇɴsɪᴏɴᴀʟ ғᴏʀᴍᴜʟᴀ ᴏғ ᴍᴏᴍᴇɴᴛᴜᴍ
=>ᴘ = [ᴍ]x [ʟᴛ^(-1)]
ᴄᴏɴsᴇʀᴠᴀᴛɪᴏɴ ᴏғ ᴍᴏᴍᴇɴᴛᴜᴍ:-
ʟᴀᴡ ᴏғ ᴄᴏɴsᴇʀᴠᴀᴛɪᴏɴ ᴏғ ᴍᴏᴍᴇɴᴛᴜᴍ ɪs ᴅᴇғɪɴᴇᴅ ᴀs ᴀ ᴘʀɪɴᴄɪᴘʟᴇ ɪɴ ᴘʜʏsɪᴄs ᴛʜᴀᴛ sᴛᴀᴛᴇs ᴛʜᴀᴛ ғᴇᴡ ᴘᴀʀᴛs ɪɴ ᴀɴ ɪsᴏʟᴀᴛᴇᴅ sʏsᴛᴇᴍ ʀᴇᴍᴀɪɴɪɴɢ sᴛᴇᴀᴅʏ ᴀɴᴅ ᴜɴᴄʜᴀɴɢɪɴɢ ᴏᴠᴇʀ ᴛɪᴍᴇ ᴇᴠᴇɴ ᴡʜᴇɴ ᴏᴛʜᴇʀs ᴀʀᴇ ᴍᴏᴠɪɴɢ.