Question

if(x-2) is a zero of x³-4x²+kx-8then find k.​

Answer 1

Answer:

put x= 2 in equation and solve

Answer 2

Answer:

x-2=0

x=2

x^3-4x^2+kx-8=0

2^3-4(2^2)+k*2-8=0

8-16+2k-8=0

8-24+2k=0

2k=24-8

2k=16

k=16/2

k=8

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