The filament of an electric lamp draws a current of 0.4 ampere which is lighted for 3 hours calculate the amount of charge flows through the circuit. How many moles of electrons are passing in this time.
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Total charge = 4320 C
moles of electron ≈ 0.0448 moles.
Explanation:
Since Q = i × t
Q = 0.4 × 3 × 60 × 60 Coulombs
Q = 4320 Coulombs.
Now, since one mole of electron carries a charge equal to 1 Faraday (≈96485 C)
So, total moles of electrons passing through the filament during this time will be
n = moles
n ≈ 0.0448 moles.
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