Question

if x=-2 is a zeros of the polynomial x^2+px+3.find the value of p

Answer 1

Let p(x)=x^2+px+3
x=-2 is a zero of p(x)
So, When x=-2, p(x)=0
or, (-2)^2 +p(-2) +3 = 0
or, 4-2p+3=0
or, 2p=1
or, p=1/2
Cheers!!

Answer 2

x^2 +px +3
(-2)^2 + p(-2) +3 =0
4 -2p + 3 =0
7 -2p =0
7 = 2p
7/2 = p
3•5 =p