Question

If (x-2) is actorial of the polynomial x^4-2x^3+ax-1, then the value of a is

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Answer 1

Step-by-step explanation:

Using Factor Theorem ,

x-2 = 0

x = 2

On putting, this value in the dividend ,

${x}^{4} - 2 {x}^{3} + ax - 1$

${2}^{4} - 2 \times {2}^{3} + 2a - 1 = 0$

$16 - 16 + 2a - 1 = 0$

$2a = 1$

$a = \frac{1}{2}$

Therefore, it is your answer.

I hope it helps you. If you have any doubts, then don't hesitate to ask.

Answer 2

Answer:

step by step explanation