Question

If (x-2) is factor of x^4-16 then find remainder

Answer 1

by remainder theorem

p(x) =x⁴-16

x-2=0

x=2

p(2)=2⁴-16

p(2)=16-16

p(2)=0

therefore,

remainder is 0

Answer 2

If (x - 2) is factor of $x^4-16$, then the remainder is zero(0).

Step-by-step explanation:

Let P(x) = $x^4-16$

To find, the value of remainder = ?

∵ (x - 2) is factor of P(x) = $x^4-16$

∴ x - 2 = 0

⇒ x = 2

Using remainder theorem , we get

Put x = 2 in P(x), we het

∴ $P(2) = 2^4-16$

⇒ P(2) = 16 - 16

⇒ P(2) = 0

∴ The remainder = 2

Thus, if (x - 2) is factor of $x^4-16$, then the remainder is zero(0).