Question

If x=2 is one root of the quadratic equation x square-2k-6. Find the value of k

Answer 1

$hey \: mate \: here \: is \: your \: answer...$
$x {}^{2} - 2k - 6 = 0$
$\: \: \: \: on \: putting \: x = 2$
$(2) {}^{2} - 2k - 6 = 0$
$4 - 2k - 6 = 0$
$- 2 - 2k = 0$
$- 2k = 2$
$k = \frac{ 2}{ - 2}$

$k = - 1$

$the \: value \: of \: k \: is \: - 1$



$hope \: it \: helps....$

Answer 2

$\bold{Answer :}$

Let, f (x) = x² - 2k - 6

Since x = 2 is a root of f (x),

f (2) = 0

or, 2² - 2k - 6 = 0

or, 4 - 2k - 6 = 0

or, 2k = - 2

or, k = - 1

Therefore, the value of k is (- 1)

#$\bold{MarkAsBrainliest}$