If x=2-n and y =2+n is a solution of the equation 3x-2y+6=0 find the value of'n'
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Answered by
0
x=2-n
y=2+n
substituting the values of x and y in the equation 3x-2y+6=0,we get,
=>3(2-n)-2(2+n)+6=0
=>6-3n-4-2n+6=0
=>8=5n
n=5÷8
y=2+n
substituting the values of x and y in the equation 3x-2y+6=0,we get,
=>3(2-n)-2(2+n)+6=0
=>6-3n-4-2n+6=0
=>8=5n
n=5÷8
Answered by
2
x=2-n and y=2-n is solution of equation 3x-2y+6= 0.
by putting values of x and y in equation we get
3 ×(2-n)-2×(2+n)+6=0
6-3n -4 -2n+6=0
2-5n= -6
5n=8
n=8/5
by putting values of x and y in equation we get
3 ×(2-n)-2×(2+n)+6=0
6-3n -4 -2n+6=0
2-5n= -6
5n=8
n=8/5
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