If x = (2+root 5) 1/2
+(2-root 5) 1/2 and y
(2+root 5)1/2- (2-root 5) 1/2 evaluate
x2+ y²
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super question I don't know the answer
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x = √(2 + √5) + √(2 - √5) x2
= 2 + √5 + 2 - √5 + 2√(2+√5)(2-√5)
= 4 + 2√(2+√5)(2-√5) y
= √(2+√5) - √(2-√5) y2
= 2+√5 + 2-√5 - 2√(2+√5)(2-√5)
= 4-2√(2+√5)(2-√5) x2 - y2
= 4√(2+√5)(2-√5)
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