Question

if x^2+x-1/x^2-x+1 = x^3+1/x^3-1 then find x ​

Answer 1

Answer:

Let p (x) = x + 1 / x = 2

Let p (x) = x + 1 / x = 2= x + 1 = 2x

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1= 2

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1= 2So, the answer to your question is 2.

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1= 2So, the answer to your question is 2.You can also make it this way -

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1= 2So, the answer to your question is 2.You can also make it this way -x + 1/ x = 2

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1= 2So, the answer to your question is 2.You can also make it this way -x + 1/ x = 2Cubing both sides, we get -

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1= 2So, the answer to your question is 2.You can also make it this way -x + 1/ x = 2Cubing both sides, we get -x^3 + 1/x^3 + 3×x×1/x (x + 1/x) = 8

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1= 2So, the answer to your question is 2.You can also make it this way -x + 1/ x = 2Cubing both sides, we get -x^3 + 1/x^3 + 3×x×1/x (x + 1/x) = 8= x^3 + 1/x^3 + 3 (x + 1/x) = 8

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1= 2So, the answer to your question is 2.You can also make it this way -x + 1/ x = 2Cubing both sides, we get -x^3 + 1/x^3 + 3×x×1/x (x + 1/x) = 8= x^3 + 1/x^3 + 3 (x + 1/x) = 8= x^3 + 1/x^3 + 3 × 2 = 8 (since, x + 1/ x = 2)

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1= 2So, the answer to your question is 2.You can also make it this way -x + 1/ x = 2Cubing both sides, we get -x^3 + 1/x^3 + 3×x×1/x (x + 1/x) = 8= x^3 + 1/x^3 + 3 (x + 1/x) = 8= x^3 + 1/x^3 + 3 × 2 = 8 (since, x + 1/ x = 2)= x^3 + 1/x^3 = 8 - 6

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1= 2So, the answer to your question is 2.You can also make it this way -x + 1/ x = 2Cubing both sides, we get -x^3 + 1/x^3 + 3×x×1/x (x + 1/x) = 8= x^3 + 1/x^3 + 3 (x + 1/x) = 8= x^3 + 1/x^3 + 3 × 2 = 8 (since, x + 1/ x = 2)= x^3 + 1/x^3 = 8 - 6or, x^3 + 1/x^3 = 2.

Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1= 2So, the answer to your question is 2.You can also make it this way -x + 1/ x = 2Cubing both sides, we get -x^3 + 1/x^3 + 3×x×1/x (x + 1/x) = 8= x^3 + 1/x^3 + 3 (x + 1/x) = 8= x^3 + 1/x^3 + 3 × 2 = 8 (since, x + 1/ x = 2)= x^3 + 1/x^3 = 8 - 6or, x^3 + 1/x^3 = 2.Hope this answer helps you out

Step-by-step explanation:

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