Question

IF X^2-X-6 AND X^2+3X-18 HAVE COMMON FACTOR (X-A) THEN FIND VAULE OF A​

Answer 1

Answer:

A=3

Step-by-step explanation:

The two equations will be equal to each other as both have the same root

So,

x-A=0

x=A

Now,

x^2-x-6=x^2+3x-18

Put the value of x in the two equations,

A^2-A-6=A^2-3A-18

A^2-A^2-A-3A=-18+6

-4A=-12

A=-12/-4

A=3

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Answer 2

                                                                                                   

• Answer:
• $a = 15$

                                                                                                       

• solution

                                                                                                       

if x -a i s the factor of both  equation 1 and 2

take any one equation and using reminder theorem and solve

i take 2 equation = $x^{2}+3 x-18$

then,

$x-a = 0$

$x=a$ put the value in equation $f(x)=$ $x^{2}+3 x-18$

  $f(a)$ ⇒ $a^{2} +3a-18=0$

         ⇒$a^{2} +3a=18$

         ⇒$a^{2}=18-3a$

        ⇒$\frac{a^{2}}{a}$ = $18 - 3$

        ⇒$a = 15$

                                                                                                       

may be it is helpful for you