Question

if x-2,x,x+3 are in GP find X​

Answer 1

Answer:

6

Step-by-step explanation:

$\frac{x}{x-2}$=$\frac{x+3}{x}$

$x^{2}$=$x^{2}$+x-6

x=6

Answer 2

Answer:

since it is in gp then b^2=ac

x^2=(x-2)(x+3)

x^2=x^2+3x-2x-6

0=x-6

x=6

xsq is get cancel