Question

if x^2(x+y+z)=36,y^2(x+y+z)=46,z^2(x+y+z)=63,xy(x+y+z)=111,yz(x+y+z)=99,zx(x+y+z)=82, then x?​

Answer 1

Answer:

Step-by-step explanation:

Combine all equations

i.e add all equations

x+y+z is common term

(x+y+z)(x^2+y^2+z^2+2xy+2yz+2xz)=36+46+63+2*111+2*99+2*82

(x+y+z)(x+y+z)^2=36+46+63+222+198+164

(x+y+z)^3=729

x+y+z=9

Then x^2(x+y+z)=36

x^2(9)=36

x^2=4

x=2 or -2