if x=2, y= -1 is a solution of the equation 2x+3y=k then the value of k is ????
Answers
Answered by
18
Hii There!!!
It is given that x = 2 and y = -1 are the solutions of the given equation
![\color{Orange}{2x + 3y=k ----1)} \color{Orange}{2x + 3y=k ----1)}](https://tex.z-dn.net/?f=%5Ccolor%7BOrange%7D%7B2x+%2B+3y%3Dk+----1%29%7D)
So, substitute these values in equation 1) we have :-
2 × ( 2 ) + 3 × ( -1 ) = k
=> 4 - 3 = k
=> 1 = k
Hence, the value required value is
.
_________________________
# ¢'$ #
Hope it helps :)
It is given that x = 2 and y = -1 are the solutions of the given equation
So, substitute these values in equation 1) we have :-
2 × ( 2 ) + 3 × ( -1 ) = k
=> 4 - 3 = k
=> 1 = k
Hence, the value required value is
_________________________
# ¢'$ #
Hope it helps :)
Khushi0511:
ok
Answered by
12
QUESTION
if x=2, y= -1 is a solution of the equation 2x+3y=k then the value of k is ?
ANSWER
GIVEN. EQ
![2x + 3y = k 2x + 3y = k](https://tex.z-dn.net/?f=2x+%2B+3y+%3D+k)
GIVEN VALUES
![x = 2 x = 2](https://tex.z-dn.net/?f=x+%3D+2)
and
![y = - 1 y = - 1](https://tex.z-dn.net/?f=y+%3D++-+1)
putting both value in given EQUATION
we get
![2(2) + 3( - ) = k 2(2) + 3( - ) = k](https://tex.z-dn.net/?f=2%282%29+%2B+3%28+-+%29+%3D+k)
![4 - 3 = k 4 - 3 = k](https://tex.z-dn.net/?f=4+-+3+%3D+k)
k=1
hence value of given eq is 1
VERIFICATION
PUT VALUE OF k Let see what happened
![4 - 3 = 1 4 - 3 = 1](https://tex.z-dn.net/?f=4+-+3+%3D+1)
1=1
hence proved
if x=2, y= -1 is a solution of the equation 2x+3y=k then the value of k is ?
ANSWER
GIVEN. EQ
GIVEN VALUES
and
putting both value in given EQUATION
we get
k=1
hence value of given eq is 1
VERIFICATION
PUT VALUE OF k Let see what happened
1=1
hence proved
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