Question

If x= -2,y=1 then the value of x2-4xy+y2 is

Answer 1

x^2 - 4xy + y^2 at x = -2 and y = 1 is:

(-2)^2 - 4(-2)(1) + (1)^2

= 4 + 8 + 1

= 13

Hence, If x= -2,y=1 then the value of x2-4xy+y2 is 13.

Answer 2

Answer:

x2-4xy+y2

(-2)2-4(-2)1+1*2

-4+8+2

-4+10

6..ans

HOPE IT HELPS!!