Question

If x^2+ y^2=13 and xy=6, find x-y

Answer 1

Answer:

1

Step-by-step explanation:

We Know,

(x-y)^2= x^2+y^2-2xy

=>x-y=√x^2+y^2-2xy

=√13-2×6

=√13-12

=√1=1

Answer 2

Answer:

1

Step-by-step explanation:

(x-y)² = x² +y² - 2xy

(x -y )² = 13 -2(6)

(x-y)² = 13 - 12

(x-y) ² = 1

(x- y)= 1