Question

if x^2+y^2=29xy then prove that 2log(x-y)=3log3+logx+logy​

Answer 1

Answer:

Step-by-step explanation:

⇒ x^2 + y^2 = 29xy

⇒ x^2 + y^2 = 27xy + 2xy

⇒ x^2 + y^2 - 2xy = 27xy

⇒ ( x - y )^2 = 27xy

   ⇒ log( x - y )^2 = log( 27xy )

 Using the properties of log:

⇒ 2log( x - y ) = log( 27 * x * y )

⇒ 2 log( x - y ) = log27 + log x + log y

⇒ 2 log( x - y ) = log3^3 + log x + log y

⇒ 2 log( x - y ) = 3 log3 + logx + logy

     Proved

Answer 2

Answer:

I hope that this answer helps you