Question

if x^2+y^2=4then dy/dx=​

Answer 1

$\tt {x}^{2} + {y}^{2} = 4 \\ \\ \tt Differentiating \: w.r.t \: x \\ \\ \tt \implies 2x + 2y\frac{dy}{dx} = 0 \\ \\ \tt \implies \frac{dy}{dx} = \frac{-x}{y} \\ \\ \tt \therefore \boxed{\bold{\underline{\red{\tt \frac{dy}{ex} = \frac{-x}{y} }}}}$

Answer 2

Answer:

x² + y² = 4

Differentiating w.r.t.x.

dy/dx → d/dx (x²) + d/dx (y²) = 4

→ 2x + 2y = 4

→ 2(x + y) = 4

→ x + y = 2

Hope it help you :-)