If x^2 + y^2 and x-y is 3 then find x^3 - y^3
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Answer:
0
Step-by-step explanation:
X²+y²=3
X-y = 3
Expanding x-y=3 by squaring,
(x-y)² = 3²
X²+y²-2xy=9
Substituting value of x²+y²
3-2xy=9
-2xy = 6
2xy = - 6
xy = - 3
X³-y³ = (x-y) (x²+xy+y²)
= 3 ( 3 - 3)
= 3 (0)
= 0
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