Question

If x^2+y^2+z^2 and xy+yz+zx=12,then find the value of x+y+z​

Answer 1

Step-by-step explanation:

(x+y+z)^2=x^2+y^2+z^2+2(xy+yz+zx)

or(x+y+z)^2=12+2×12

=12+24

(x+y+z)^2 =36

or (x+y+z)^2=

$\sqrt{36} = 6$