Question

If x=-2 y=3 1/2 and z= 1/2 find the value of x+y+z/xyz

Answer 1

Answer:

jsj,ndoaoakskdodmdidndkdekndkdosw

Answer 2

Answer:

3

Explanation:

What I am going to use is the simple arithmetic geometric inequality.

(a1+a2+a3+……….+an)/n>=(a1.a2.a3………an)^(1/n)……(A)

Suppose question is

(a1+a2+a3+…an)=(a1.a2.a3.a4……an)

By equation (A)

(a1+a2+a3+…an)=((a1+a2+a3+….+an)/n)^(1/n)

Let ((a1+a2+a3+…an)=a

Then we can write

a=(a/n)^(1/n)

Or a^(n-1)=n^n

(a1+ ka+a3+…=n+an)=n^(n/(n-1))=n.n(1/(n-1))=(n^(1/n-1))^n=(a1.a2.a3…..an)

If we observe the above expression carefully the we got the solution.It seems that all value all equal to n^(1/(n-1)).Just check it.

For the question

x+y+z=x.y.z

n=3 So solution will be

x=y=z=3^(1/(3–1))=3^1/2=√3