Question

If x=2,y=3 is a solution of 4x-3y+√k=0,then find the value of k.

Answer 1

QUESTION:- If x=2,y=3 is a solution of 4x-3y+√k=0,then find the value of k.

ANSWER:- VALUES X=2 , Y= 3

$4x - 3y + \sqrt{k} =0 \\ \\ 4(2) - 3(3) + \sqrt{k} = 0 \\ \\ 8 - 9 + \sqrt{k} = 0 \\ \\ - 1 + \sqrt{k} = 0 \\ \\ \sqrt{k} = 1 \\ \\ k = \sqrt{1} \\ \\ k = 1$

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