if x=2,y=3 is a solution of a pair of lines 2x-3y+a=0 and 2x+3y-b+2=0,then
(a):a=3b (b) a+3b=0 (c) 3a+b=0 (d) 3a=b
Answers
Answered by
1
Answer:
(d) 3a=b
Step-by-step explanation:
X=2
y=3
2x-3y+a=0
(2×2)-(3×3)+a=0
4-9+a=0
-5+a=0
a=5
2x+3y-b+2=0
(2×2)+(3×3)-b+2=0
4+9-b+2=0
15=0
Option D ✅
3a=b
3×5=15
15=15
Answered by
2
Answer:
X=2
y=3
2x-3y+a=0
(2×2)-(3×3)+a=0
4-9+a=0
-5+a=0
a=5
2x+3y-b+2=0
(2×2)+(3×3)-b+2=0
4+9-b+2=0
15=0
Option D ✅
3a=b
3×5=15
15=15
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