If x= -2,y=6 is the solution of equation 3ax + 2ay =6 then find value of b from 2(a-1)+2(3b-4)=4.
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Answered by
6
put value of x and y in equation
3ax + 2ay =6
so, 3 a(-2) + 2a(6) = 6
-6a + 12a =6
6a =6
a =1
put a value in eq. 2(a-1) + (3b-4) =4
so, 2 (1-1) + 2(3b -4 ) = 4
0+ 6b - 8 = 4
6b =4+8
6b = 12
b= 2
3ax + 2ay =6
so, 3 a(-2) + 2a(6) = 6
-6a + 12a =6
6a =6
a =1
put a value in eq. 2(a-1) + (3b-4) =4
so, 2 (1-1) + 2(3b -4 ) = 4
0+ 6b - 8 = 4
6b =4+8
6b = 12
b= 2
Answered by
6
x=-2
y=6
3ax+2ay=6
-6a+12a=6
6a=6
a=1
2(a-1)=2a-2=2-2=0
2(3b-4)=6b-8
0+6b-8=4
6b=12
b=2
y=6
3ax+2ay=6
-6a+12a=6
6a=6
a=1
2(a-1)=2a-2=2-2=0
2(3b-4)=6b-8
0+6b-8=4
6b=12
b=2
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