Math, asked by khushi950, 1 year ago

if x=2-y show that x^3 + 6xy + y^3 -8 ==0

Answers

Answered by yeshq
2
x=2 then 2-y^3 +6*2-y*y+y^3-8=0
6-y+12-y*y+3y-8
10-2y+3y*y
10+y*y=0
10+y^2=0
y^2=-10
y=√+-10
if understood please select as brainlilest
Similar questions