If x=2-y,then the value of x³+6xy+y³-8 is
Answers
Answered by
1
If x = 2 - y
Then ,
x³ + 6xy + y³ - 8 = 0
( 2 - y )³ + 6 ( 2 - y ) y + y³ - 8 = 0
-y³ + 6y² - 12y + 8 - 6y² + 12y + y³ - 8 = 0
0 = 0
Then ,
x³ + 6xy + y³ - 8 = 0
( 2 - y )³ + 6 ( 2 - y ) y + y³ - 8 = 0
-y³ + 6y² - 12y + 8 - 6y² + 12y + y³ - 8 = 0
0 = 0
Answered by
1
Answer:
take it easy bro
put the value of x on p(x)
I m just giving hint
hope it will help you
Attachments:
Similar questions