Question

if x = (27)1/3 and y = (28)1/3, then the value of x+y-1/(x²+xy+y²) is

Answer 1

something is missing here,
(y -x) in place (x +y) you take ,

x = (27)⅓ and y = (28)⅓

(y-x) - 1/(x² +xy +y²)

{(y - x)(x²+xy+y²) -1 }/(x²+xy+y²)

use formula,

(a-b)(a²+ab+b²) = a³ -b³

now,

{ y³ - x³ -1}/(x² +xy +y²)

(28 -27 -1)/(x²+xy+y²)

0 ( answer )

Answer 2

your Question is correct

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