Question

if x=-2and y=1 by using identity find the value of (4y^2-8x^2) (16y^4+36x^2y^2+81x^4)
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Answer 1

Answer:

Hey friend

here is the answer you were looking for

(4y^2-9x^2)(16y^4+36x^2y^2+81x^4)

(4*1-9*4)(16*1+36*4*1+81*16)

(4-36)(16+144+1296)

-32*1456

=-46592

thanks

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