Question

If x=2andx=3 are roots of the equation 3x2+2kx+2m=0 then find (k,m).

Answer 1

The value of k=152andm=9.k=152andm=9.

Since roots have been given to us so we can make a quadratic equation like (x−2)(x−3).(x−2)(x−3).

(x−2)(x−3)=x2−5x+6(x−2)(x−3)=x2−5x+6

now comparing the equation x2−5x+6x2−5x+6with the given equation 3x2−2kx+2m.3x2−2kx+2m.

Rewrite the given equation as x2−2k3x+2m3=0x2−2k3x+2m3=0

we get 2k=152m=182k=152m=18

so k=15/2andm=9.

Answer 2

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