Question

can anybody do question no 14

Answer 1

Hola there,

=> ${5}^{2x - 1} = \frac{1}{( {125)}^{x - 3} }$

=> ${5}^{2x - 1} = \frac{1}{ {(5)}^{3(x - 3)} }$

=> ${5}^{2x - 1} = {5}^{ - 3(x - 3)}$

As, now we can see the base is same so we will now cancel out the base and then solve the power.

=>2x - 1 = -3(x - 3)

=> 2x - 1 = -3x + 9

=> 5x = 10

=> x = 2. ....Ans

Hope this helps...:)