if x=2andy=3 is a solution of 2x-3y+k=0 find the value k
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The answer is k is equal to 5
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given :-
X= 2
y= 3
substitute the values in the given equation
2x-3y+k= 0
2(2)-3(3)+k =0
4-9+k =0
-5+k =0
k= 0+5
k= 5
X= 2
y= 3
substitute the values in the given equation
2x-3y+k= 0
2(2)-3(3)+k =0
4-9+k =0
-5+k =0
k= 0+5
k= 5
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